php - mysql table update gives no result -
i made html form updates fields in table in mysql db after succeful updates should direct me success page otherwise give error msg. indicating error
i use form validation far nothing happens fields in table directs me blank page
here form code :
<html> <body> <form action="http://localhost/wordpress/orgupdate.php" method="post" name="myform"> name <input id="name" type="text" name="name" /> telephone <input id="telephone" type="text" name="telephone" /> fax <input id="fax" type="text" name="fax" /> web address <input id="webaddress" type="text" name="webaddress" /> state <input id="state" type="text" name="state" /> address <input id="address" type="text" name="address" /> <input type="submit" name= "submit" value="update" /> </form> </body> </html> <script type="text/javascript">// <![cdata[ /* js validation code here */ function validateform() { /* validating name field */ var x=document.forms["myform"]["name"].value; if (x==null || x=="") { alert("name must filled out"); return false; } /* validating email field */ var x=document.forms["myform"]["telephone"].value; if (x==null || x=="") { alert("telephone must filled out"); return false; } } // ]]> </script> and php file :
<?php //establish connection $con = mysqli_connect("localhost","xx","xxxx","android_app"); //on connection failure, throw error if(!$con) { die('could not connect: '.mysql_error()); } //get form elements , store them in variables $name=$_post['name']; $telephone=$_post['telephone']; $fax=$_post['fax']; $webaddress=$_post['webaddress']; $state=$_post['state']; $address=$_post['address']; $query= update islamic_organisation set (telephone ='$telephone', fax ='$fax', webaddress ='$webaddress', state ='$state', address ='$address' name ='$name'); //redirects specified page header("location: http://localhost/wordpress/?page_id=857"); ?> any idea ?
$query= "update islamic_organisation set telephone ='$telephone', fax ='$fax', webaddress ='$webaddress', state ='$state', address ='$address' name ='$name'"; $result=mysqli_query($con,$query) or die(mysqli_error()); edit 1:
printf("affected rows (update): %d\n", mysqli_affected_rows($con));
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