c# - How to remove items from a List of Structs that exist in another List -

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public struct registryapp {     public string vendorname;     public string name;     public string version; }

i have 2 list<registryapp> hold applications installed on windows box. why two? have 1 list hold x86 applications , 1 hold x64 applications.

list<registryapp> x64apps64list = new list<registryapp>(); list<registryapp> x64apps32list = new list<registryapp>();

once 2 populated appropriate data retrieved registry, try following make sure there no duplicates. worked decently on list<string> not working list<registryapp>.

list<registryapp> listofallappsinstalled = new list<registryapp>();  ienumerable<registryapp> x86apps = x64apps32list.except(x64apps64list); ienumerable<registryapp> x64apps = x64apps64list.except(x64apps32list);  foreach (registryapp regitem in x86apps) {     if ((regitem.name != null) &&       (regitem.name.length > 2) &&       (regitem.name != ""))      {         listofallappsinstalled.add(regitem);     } }  foreach (registryapp regitem in x64apps)  {     if ((regitem.name != null) &&       (regitem.name.length > 2) &&       (regitem.name != ""))      {         listofallappsinstalled.add(regitem);     } }

any way pull off?

edited

to remove items list of structs exist in list can see solution provided cuong le here :

https://stackoverflow.com/a/12784937/1507182

by using distinct parameterless extension method on list type, can remove duplicate elements.

then, can optionally invoke tolist extension actual list duplicates removed.

static void main()     {     // list duplicate elements.     list<int> mylist = new list<int>();     mylist.add(1);     mylist.add(2);     mylist.add(3);     mylist.add(3);     mylist.add(4);     mylist.add(4);     mylist.add(4);      foreach (int value in mylist)     {         console.writeline("before: {0}", value);     }      // distinct elements , convert list again.     list<int> distinct = mylist.distinct().tolist();      foreach (int value in distinct)     {         console.writeline("after: {0}", value);     }     }

if answer has solved problem click accept solution button, doing others know solution.


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