regex - How to match start and end of a string? -

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i'm trying use notepad++'s find & replace regular expression on following sample:

 3   733xxxx (-1)  3  1521xxxx (-1)  3  1521xxxx (-1)

how can keep following unmatched?

733xxxx 1521xxxx 1521xxxx

i've tried using following expressions:

^(.* \(-1\)).*$ ^(\(-1\))$

the first 1 matches everything, second: nothing.

can point me in right direction?

there several ways approach this:

  • replace "^ *\d+ +" , " *\(-1\)$" (the quotes clarity) empty string (2 steps)

  • replace "^ *\d+ +(\d+).*$" $1

\d short-hand character class, matches whatever [[:digit:]] matches (numeric digits). (notepad++ uses boost regex). testing, seems it can match unicode numeric digits, don't think going matter in application.

the ^ *\d+ + part match text before numbers in middle.

 *\(-1\)$ matches spaces , (-1) @ end of line.

for ^ *\d+ +(\d+).*$, regex match whole line, retain part want, numbers in middle. () (which not escaped in  *\(-1\)$) capturing group, captures text sub-pattern matches. don't care text following captured number, use .* match everything.


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