c - Why am I getting the error "Break statement not within loop or or switch."? -

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this simple program asks use's age , based on displays message.at end if it,the user asked if repeat whole thing again.but getting error

break statement not within loop or switch

when compile it. mean , how correct it?

#include <stdio.h> #include <string.h>  static int prompt_continue (const char *prompt)    {        printf("%s", prompt);        char answer[5];        if (scanf("%1s", answer) != 1)      return 0;         if (answer[0] == 'y' || answer[0] == 'y')  {     int c;     while ((c = getchar()) != eof && c != '\n')     ;     return 1; } return 0;    }     int main(void) { /*creates simple program using if else example. */    int age;     while (printf("welcome, program designed if else statements.\n"));    printf("please enter age.\n");     scanf (" %d", &age); /*enters age.*/    if (age < 18){    printf("you young!\n"); }  else if (age > 18){     printf("ah you're old!\n");   }    {     printf(" woot.\n");     if (prompt_continue("do want try again? y/n") == 0)     break;   }       return 0; }

just trying work through this, need little help. did use while loop wrong? thoughts helpful. thanks!

you need define scope of loop. in code:

while (printf("welcome, program designed if else statements.\n")); printf("please enter age.\n"); ... if (prompt_continue("do want try again? y/n") == 0)     break;

what need is:

while (true) {     printf("welcome, program designed if else statements.\n"));     printf("please enter age.\n");     ...     if (prompt_continue("do want try again? y/n") != 1)         break; }

break stops execution of while loop here.


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