java - Calculating percentage of a map values -

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made program counts number of occurrences of letters in given string using treemap(string, integer) (named alphafreq). want represent these occurrences percentages ([a=12.3] , [b=3.0] , ....etc), created treemap (string, double) (named percentage), copied keys values set zero, , edited value according in alphafreq follows: 

for(int i=0; i<26; i++){    int temp;    character current = (char)(i+65);    string frog = current.tostring();    temp = alphafreq.get(frog);    int perc = (temp/cipherletters.length)*100;    system.out.println(temp+"/"+cipherletters.length+" = "+perc);    percentage.put(frog,(double)perc); }

if string or bs, result keys have value of 0 except a=100.0 or b=100.0 if string text has other combination (say: ddjjshhiem) have value of zero. why? doing wrong?................thanks

first thing change calculation of percentage to:

int perc = (temp * 100)/cipherletters.length;

given using integer division, (temp/cipherletters.length) zero.


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