linux - Cutting the column including size -

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i want cut column include size of files . use ls -l view info files in current localization . save info file in txt file ls -l > info.txt , , want cut column including size . cat info.txt | cut -d'' -f6 don't work . wrong ?

this include info.txt :

-rwx------ 1 s10891 domain users   2188 may  4 14:51 info.txt -rwx------ 1 s10891 domain users   1640 mar 10 07:43 code.txt -rwx------ 1 s10891 domain users     68 mar  4 11:59 sorted.txt drwx------ 1 s10891 domain users      0 jan 11 09:48 ppj drwx------ 1 s10891 domain users      0 sep  7  2012 public_html drwx------ 1 s10891 domain users      0 apr 15 11:16 rbd drwx------ 1 s10891 domain users      0 jan  7 09:45 rdb drwx------ 1 s10891 domain users      0 apr 15 12:00 sop drwx------ 1 s10891 domain users      0 apr  8 12:53 sop_ex3 -rwx------ 1 s10891 domain users    122 feb 25 11:48 sop_info.txt drwx------ 1 s10891 domain users  0 jan 14 09:41 windowsformsapplicati drwx------ 1 s10891 domain users      0 jan 14 09:41 windowsformsapplicati drwx------ 1 s10891 domain users      0 jan 14 09:41 windowsformsapplicati

and want : 

2188 1640 68 0 0 0 0 0 0 122 0 0 0

most cuts count literal characters, -f 6 work, data has in same columns. not sure if 3rd last line typo or exact reproduction of output, illustrates problem cut perfectly.

for case, people use awk solution:

 ls -l | awk '{print $6}'

will produce output have listed

the beauty of awk field 6 determined value of awk fs variable (field separator), defaults "multiple white space values" (space or tab) (this not exact description, close enough needs).


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